If it's not what You are looking for type in the equation solver your own equation and let us solve it.
100x^2+60x-19=0
a = 100; b = 60; c = -19;
Δ = b2-4ac
Δ = 602-4·100·(-19)
Δ = 11200
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{11200}=\sqrt{1600*7}=\sqrt{1600}*\sqrt{7}=40\sqrt{7}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(60)-40\sqrt{7}}{2*100}=\frac{-60-40\sqrt{7}}{200} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(60)+40\sqrt{7}}{2*100}=\frac{-60+40\sqrt{7}}{200} $
| x/3-4=19 | | 80=x/3+x/5 | | -16t^2+24t-9=0 | | y12=(-6) | | x-0.2x=199 | | (y-3)-4y=-3y-3 | | -11-13z-9=3(-8z+20)+19 | | c/7-3=21 | | 2^x+9•(2^x)+4=0 | | 3^0.5x=81 | | 9(r+3)-2r=-12(r-7) | | 3(12)+y=6y+2(12)-13 | | 2(6+2r)=-4(r+3) | | 4d+5-2=6 | | -4(-11x+9)=-6(6+5x) | | 8-2r-10+9r=3 | | 2x=9+5x | | 5k^2+7k+6=0 | | 56+2x-x^2=7 | | (1.165+0.7683+0.88+1.825)/6=x | | 3×(x+-7)=12 | | 1x^-3=247 | | 8x+2=7× | | (x+1)^0.5-(x-1)^0.5-(4x-1)^0.5=0 | | (1/45)*100=x | | x3+7=5 | | -6(14g-12)=-9-3g | | 4x-4x2=0 | | 5k^2+7k-3=0 | | 1,5x2-0,5x=0 | | 7x+3=9x-3-2× | | 3x2+4x=0 |